Bandit1017 Bandit1017
  • 03-06-2019
  • Mathematics
contestada

Which restriction is appropriate for the variable 4a + 12 / a + 3

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DeanR
DeanR DeanR
  • 03-06-2019

I'll presume the slash is the fraction bar and the questioner is asking about

[tex]\dfrac{4a+12}{a+3}[/tex]

That always equals 4 except when [tex]a=-3[/tex]

So the restriction is

Answer:  a ≠ -3

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gr1212 gr1212
  • 03-06-2019

Answer:

The restriction is at a=-3

Step-by-step explanation:

You need to see if there are like terms. If there are that is a hole. For example you can a 4 out of the equation like so.

4(a+3)/a+3.

since they both have a+3 that is a hole. so a+3=0 so a=-3 is a restriction

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