Answer:
The answer to your question is E = 419.435 J
Explanation:
Data
Mass = m = 2.004 g
Temperature 1 = T1 = 89°C
Temperature 2 = T2 = 139°C
Specific heat of water = Cp = 4.186 J/g°C
Energy = E = ?
Formula
E = mCp(T2 - T1)
Substitution
E = (2.004)(4.186)(139 - 89)
Simplification and result
E = 8.3887(50)
E = 419.435 J
