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02-03-2020
Mathematics

contestada

The first four terms in a sequence are 80, 74, 68, 62, ....
What is the 14th term in the sequence?

Respuesta :

PollyP52 PollyP52

02-03-2020

Answer:

2.

Step-by-step explanation:

This is arithmetic sequence with common difference -6 and first term 80,

nth term = a1 + d(n - 1) so:

14th term = 80 - 6(14 - 1)

= 80 - 6*13

= 80 - 78

= 2.

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[tex]y = 3x - 2 \\ y - 2 = x[/tex]that's the problem