erin91
erin91 erin91
  • 01-04-2020
  • Chemistry
contestada

What mass of H2SO4 would be required to react with 0.75 mil NaOH

Respuesta :

Tringa0 Tringa0
  • 02-04-2020

Answer:

36.75 grams of sulfuric acid will be required.

Explanation:

Moles of sodium hydroxide = 0.75 mol

[tex]2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O[/tex]

According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid ,then 0.75 moles of NaOH will :

[tex]\frac{1}{2}\times 0.75 mol=0.375 mol[/tex] sulfuric acid

Mass of 0.375 moles of sulfuric acid:

0.375 mol × 98 g/mol = 36.75 g

36.75 grams of sulfuric acid will be required.

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