Answer:
 y = x -6
Step-by-step explanation:
The question is asking what system of equations is equivalent to the quadratic given, where one of the equations in the system is y = x^2 -1.
Let's say the other equation is ...
 y = mx +b
So, equating the values of y, we would have ...
 x^2 -1 = mx +b
Subtracting the right side gives ...
 x^2 -mx -1 -b = 0
Now, we can equate coefficients to y=x^2 -x +5 and we will see that ...
 -mx = -1x  ⇒  m = 1
 -1 -b = +5  ⇒  b = -6
The other line has the equation ...
 y = x -6
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Comment on the problem
The given quadratic, and the equivalent system of equations we found, have no real solutions.
