valdezaze9229 valdezaze9229
  • 01-10-2021
  • Physics
contestada

A stone is dropped into a well and is heard to hit the water 2.27 s after being dropped. Determine the depth of the well.​

Respuesta :

ChemMajor ChemMajor
  • 01-10-2021

Answer:

25.25m

Explanation:

The Depth or distance would be:

d = acceleration x time² / 2

If the stone was held at a dead stop until dropped, acceleration is equal to gravity which is 9.8 m/s²

So then you have:

d = (9.8m/s²)(2.27s)² / 2  or (9.8m/s²)(2.27s)(2.27s) / 2

the seconds cancel each other out and you're left with meters.

d = 25.25 m

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